Help with counting Query

I am trying to find a query to count rows with multiple conditions.
I have files which are suffixed with -R and then a number from 1 to 3 and
then two digits 00-14.
the field is char
i.e.:
-R101
-R102
-R114
-R201
-R302
I need to determine how many 101, how many 102, etc through 114 and then the
same for
the 201-214 series and then
the 301-314 series.
I will be sending the query from Visual Basic using ADODC so I am not sure
how the data will be returned. If it was written to a temp table that would
be great.
Thanks,
Bob Hiller
Lifts for the Disabled LLCselect right(columnName, 3), count(columnName)
from tableName
group by right(columnName, 3)
"Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
news:ecFHqw3TGHA.5464@.TK2MSFTNGP10.phx.gbl...
>I am trying to find a query to count rows with multiple conditions.
> I have files which are suffixed with -R and then a number from 1 to 3 and
> then two digits 00-14.
> the field is char
> i.e.:
> -R101
> -R102
> -R114
> -R201
> -R302
> I need to determine how many 101, how many 102, etc through 114 and then
> the same for
> the 201-214 series and then
> the 301-314 series.
> I will be sending the query from Visual Basic using ADODC so I am not sure
> how the data will be returned. If it was written to a temp table that
> would be great.
> Thanks,
> Bob Hiller
> Lifts for the Disabled LLC
>
>|||Thank you,
That worked great but I did not ask the full question. Maybe you can help
again.
if these strings are in a column
12345678-R101
12345678-R201
12345678-R301
98564512-R112
18752381-R101
18752381-R201
18752381-R110
18752381-R111
18752381-R211
If there is a -R2 there will always be a -R1. Likewise if there is a -R3
there will always be a -R2.
In the above example I need to return
12345678-R301
98564512-R112
18752381-R201
18752381-R110
18752381-R211
I hope I have explained this well enough.
Thanks,
Bob Hiller
Lifts for the Disabled LLC
"Raymond D'Anjou" <rdanjou@.canatradeNOSPAM.com> wrote in message
news:uWek153TGHA.4540@.TK2MSFTNGP10.phx.gbl...
> select right(columnName, 3), count(columnName)
> from tableName
> group by right(columnName, 3)
> "Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
> news:ecFHqw3TGHA.5464@.TK2MSFTNGP10.phx.gbl...
>|||select left(columnName, charindex('-R',columnName)+1),
MAX(substring(columnName,charindex('-R',columnName)+2,10))
from tableName
group by left(columnName, charindex('-R',columnName)+1)
"Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
news:%23IRMFQ4TGHA.1204@.TK2MSFTNGP12.phx.gbl...
> Thank you,
> That worked great but I did not ask the full question. Maybe you can help
> again.
> if these strings are in a column
> 12345678-R101
> 12345678-R201
> 12345678-R301
> 98564512-R112
> 18752381-R101
> 18752381-R201
> 18752381-R110
> 18752381-R111
> 18752381-R211
> If there is a -R2 there will always be a -R1. Likewise if there is a -R3
> there will always be a -R2.
> In the above example I need to return
> 12345678-R301
> 98564512-R112
> 18752381-R201
> 18752381-R110
> 18752381-R211
> I hope I have explained this well enough.
> Thanks,
> Bob Hiller
> Lifts for the Disabled LLC
>
> "Raymond D'Anjou" <rdanjou@.canatradeNOSPAM.com> wrote in message
> news:uWek153TGHA.4540@.TK2MSFTNGP10.phx.gbl...
>|||OOPS... You need to convert the count values to int...
select left(columnName, charindex('-R',columnName)+1),
MAX(convert(int,substring(columnName,cha
rindex('-R',columnName)+2,10)))
from tableName
group by left(columnName, charindex('-R',columnName)+1)
"helpful sql" <nospam@.stopspam.com> wrote in message
news:OLQc8X4TGHA.424@.TK2MSFTNGP12.phx.gbl...
> select left(columnName, charindex('-R',columnName)+1),
> MAX(substring(columnName,charindex('-R',columnName)+2,10))
> from tableName
> group by left(columnName, charindex('-R',columnName)+1)
> "Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
> news:%23IRMFQ4TGHA.1204@.TK2MSFTNGP12.phx.gbl...
>|||I will do some more checking but thus far your very appreciated suggestion
is producing some very strange results.
For one thing it is returning 2 expressions. I would expect only one.
Thanks,
Bob Hiller
Lifts for the Disabled LLC
"helpful sql" <nospam@.stopspam.com> wrote in message
news:OsGYae4TGHA.4792@.TK2MSFTNGP14.phx.gbl...
> OOPS... You need to convert the count values to int...
> select left(columnName, charindex('-R',columnName)+1),
> MAX(convert(int,substring(columnName,cha
rindex('-R',columnName)+2,10)))
> from tableName
> group by left(columnName, charindex('-R',columnName)+1)
> "helpful sql" <nospam@.stopspam.com> wrote in message
> news:OLQc8X4TGHA.424@.TK2MSFTNGP12.phx.gbl...
>|||Ok, I can live with the 2 returned expressions, they will work fine.
Here is what is returned when I run the sample:
12345678-R301
98564512-R112
18752381-R211
I am missing:
18752381-R201
18752381-R110
Think of the first number after the -R as a counter for the last 2 numbers
that represent a group.
When these are in the table
18752381-R101 01 is the group and 1 is the counter
18752381-R201 01 is the group and 2 is the counter
we want to return the largest counter for group 01 for the number to the
left of -R
return (18752381-R201)
18752381-R110 10 is the group and 1 is the counter
return (18752381-R110) it is the only group 10 for the number to the left
of -R
18752381-R111 11 is the group and 1 is the counter
18752381-R211 11 is the group and 2 is the counter
return (18752381-R211)
Thank in advance,
Bob Hiller
Lifts for the Disabled LLC
"helpful sql" <nospam@.stopspam.com> wrote in message
news:OsGYae4TGHA.4792@.TK2MSFTNGP14.phx.gbl...
> OOPS... You need to convert the count values to int...
> select left(columnName, charindex('-R',columnName)+1),
> MAX(convert(int,substring(columnName,cha
rindex('-R',columnName)+2,10)))
> from tableName
> group by left(columnName, charindex('-R',columnName)+1)
> "helpful sql" <nospam@.stopspam.com> wrote in message
> news:OLQc8X4TGHA.424@.TK2MSFTNGP12.phx.gbl...
>|||select max(a)
from(select '12345678-R101'
union all select '12345678-R201'
union all select '12345678-R301'
union all select '98564512-R112'
union all select '18752381-R101'
union all select '18752381-R201'
union all select '18752381-R110'
union all select '18752381-R111'
union all select '18752381-R211')x(a)
group by left(a,8),right(a,2)
-oj
"Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
news:Ow6lDS5TGHA.4600@.TK2MSFTNGP11.phx.gbl...
> Ok, I can live with the 2 returned expressions, they will work fine.
> Here is what is returned when I run the sample:
> 12345678-R301
> 98564512-R112
> 18752381-R211
> I am missing:
> 18752381-R201
> 18752381-R110
> Think of the first number after the -R as a counter for the last 2 numbers
> that represent a group.
> When these are in the table
> 18752381-R101 01 is the group and 1 is the counter
> 18752381-R201 01 is the group and 2 is the counter
> we want to return the largest counter for group 01 for the number to the
> left of -R
> return (18752381-R201)
> 18752381-R110 10 is the group and 1 is the counter
> return (18752381-R110) it is the only group 10 for the number to the
> left of -R
> 18752381-R111 11 is the group and 1 is the counter
> 18752381-R211 11 is the group and 2 is the counter
> return (18752381-R211)
> Thank in advance,
> Bob Hiller
> Lifts for the Disabled LLC
>
> "helpful sql" <nospam@.stopspam.com> wrote in message
> news:OsGYae4TGHA.4792@.TK2MSFTNGP14.phx.gbl...
>|||oj,
Thanks for the suggestion but the values where just given as samples. There
are thousands of rows that I have to search through. I don't think this
approach will work.
Thanks,
Bob Hiller
Lifts for the Disabled LLC
"oj" <nospam_ojngo@.home.com> wrote in message
news:e%23xZMS6TGHA.5108@.TK2MSFTNGP11.phx.gbl...
> select max(a)
> from(select '12345678-R101'
> union all select '12345678-R201'
> union all select '12345678-R301'
> union all select '98564512-R112'
> union all select '18752381-R101'
> union all select '18752381-R201'
> union all select '18752381-R110'
> union all select '18752381-R111'
> union all select '18752381-R211')x(a)
> group by left(a,8),right(a,2)
>
> --
> -oj
>
> "Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
> news:Ow6lDS5TGHA.4600@.TK2MSFTNGP11.phx.gbl...
>|||Bob,
You need to adapt the technique to your data.
e.g.
select max(your_col)
from tb
group by left(your_col,8),right(your_col,2)
If it does not give you the desired result, you'd want to post ddl + sample
data + expected result here so we can help.
-oj
"Bob and Sharon Hiller" <aoklans@.tir.com> wrote in message
news:uRMPBI8TGHA.5836@.TK2MSFTNGP10.phx.gbl...
> oj,
> Thanks for the suggestion but the values where just given as samples.
> There are thousands of rows that I have to search through. I don't think
> this approach will work.
> Thanks,
> Bob Hiller
> Lifts for the Disabled LLC
> "oj" <nospam_ojngo@.home.com> wrote in message
> news:e%23xZMS6TGHA.5108@.TK2MSFTNGP11.phx.gbl...
>

help with complex SQL query

I need some help from prog. gurus with sql query.

I have a commodity table and I would like to pull information from it based on the conditions. I can write code to pull straight forward information from the table but I need help in writing query such that the later columns are based on the former columns.

To clear my question, I am writing the sample code below.
The column 4, 5 and 6 are based on column 1, 2, 3.
Column6 is column3/column2 (which is simple)
But column4 & 5 are too complex for me to write the code for. Column4 is the % of Quantity (cty_code)/(all countries) for that particular commodity. cty_code correspends to a country.

Table information:

[dbo].[2005exp](
[dom_or_for] [char](1) NOT NULL,
[commodity] [char](10) NOT NULL,
[cty_code] [char](4) NOT NULL,
[district] [char](2) NOT NULL,
[stat_month] [char](2) NOT NULL,
[cards_mo] [decimal](8, 0) NOT NULL,
[all_qy1_mo] [decimal](12, 0) NOT NULL,
[all_val_mo] [decimal](12, 0) NOT NULL
)

---

Table data snapshot:

Query1:
select top 10 commodity, sum(all_qy1_mo) as Quantity, sum(all_val_mo) as Price from [2005exp]
where cty_code=5310 group by Commodity order by price desc

Output:

Commodity	Quantity	Price	Column4	Column5	Price/Quantity
8517305000	0	46307629
8517905000	0	11990255
3003100000	2268	2687905	0.35%	29.92%	1185.1437
8524990000	148	1815000
8471300000	2591	1673570
9802400000	0	1560247
9880004000	0	1197407
8802300080	1	1100000
3819000000	601192	899417
9802200000	0	811996

Query2: (based on the results of query 1 i.e., commodity)
select Sum(all_qy1_mo) as Quantity, sum(all_val_mo) as Price from [2005exp]
where commodity=3003100000

Output:

Quantity	Price
645261	8982928

2268 / 645261 = 0.35% Column 4

2687905 / 8982928 = 29.92% Column 5

Quantity/Price = Average (2687906/2268 = 1185.1437) i.e. column3/column2=Column6

The final output should like: (There are additional 2 columns in the table below but they are not required)

select a.commodity, sum(a.all_qy1_mo) as Quantity, sum(a.all_val_mo) as Price,

CASE WHEN (select Sum(b.all_qy1_mo)from [2005exp] b

where a.commodity=b.commodity)<>0 THEN (sum(a.all_qy1_mo)/(select Sum(b.all_qy1_mo) from [2005exp] b

where a.commodity=b.commodity))*100.00 ELSE NULL END as col4, CASE WHEN (select sum(b.all_val_mo) from [2005exp] b where a.commodity=b.commodity)<>0 THEN (sum(a.all_val_mo)/(select sum(b.all_val_mo) from [2005exp] b where a.commodity=b.commodity))*100.00 ELSE NULL END as col5,

CASE WHEN sum(a.all_qy1_mo)<> 0 THEN sum(a.all_val_mo)/sum(a.all_qy1_mo) ELSE NULL END as col6

from [2005exp] a

WHERE a.cty_code=5310

GROUP BY a.commodity

|||

Thank you so much. The code works perfectly. I really appreciate all your help.

I wanted to add another column 7 which is column5/column4. How can I save the column5 and Column4 values in 2 different variables and then perform the division ?

I tried to use just the alias names i.e col5/col4, but its not working.

I tried using the actual code for both columns and its working but its taking 4 minutes to execute the query. Its repeating the same steps twice. How is it done right way ?

Also, I was trying to delcare a variable for the table name but without any success. Who is it done ?

Use test
Go

Declare @.Country Int
Set @.Country=5310

select top 10 a.commodity as Commodity, c.descrip_1 as Description, c.quantity_1 as Unit,

sum(a.all_qy1_mo) as Quantity, sum(a.all_val_mo) as [Value],

CASE WHEN (select Sum(b.all_qy1_mo)from [2005exp] b where a.commodity=b.commodity)<>0 THEN (sum(a.all_qy1_mo)/(select Sum(b.all_qy1_mo) from [2005exp] b where a.commodity=b.commodity))*100.00 ELSE NULL END as [U.S. Share(Quantity) %],

CASE WHEN (select sum(b.all_val_mo) from [2005exp] b where a.commodity=b.commodity)<>0 THEN (sum(a.all_val_mo)/(select sum(b.all_val_mo) from [2005exp] b where a.commodity=b.commodity))*100.00 ELSE NULL END as [U.S. Share(Value) %],

CASE WHEN sum(a.all_qy1_mo)<> 0 THEN sum(a.all_val_mo)/sum(a.all_qy1_mo) ELSE NULL END as [Average Price],

CASE WHEN (select Sum(b.all_qy1_mo)from [2005exp] b where a.commodity=b.commodity)<>0 THEN
(((sum(a.all_val_mo)/(select sum(b.all_val_mo) from [2005exp] b where a.commodity=b.commodity)))/((sum(a.all_qy1_mo)/(select Sum(b.all_qy1_mo) from [2005exp] b where a.commodity=b.commodity)))) ELSE NULL END as [Price Ratio]

from [2005exp] a inner join concord c on a.commodity=c.commodity

WHERE a.cty_code=@.Country
GROUP BY a.commodity, c.descrip_1, c.quantity_1 order by [Value] desc

Help with Case

I have the following data with following conditions:

Old Type New Type

Number: 01 in table1 with Connection : 'J' in table2 'GE'

Number: 01 in table1 with Connection : 'K' in table2 'GPE'

Number: 01 in table1 with Connection: 'L' In table2 'GPA'

Number: 02 in table1 with Connection: 'I' in table2 'I02'

I used queries like:

SELECT CASE WHEN t1.Number = '01' THEN

CASE WHEN t2.Connection = 'J' THEN 'GE'

ELSE CASE WHEN t2.Connection = 'K' THEN 'GPE'

ELSE CASE WHEN t2.Connection = 'L' THEN 'GPA'

ELSE 'NOTHING' END END END END AS NewType

FROM Table1 AS t1 LEFT JOIN Table2 AS t2

ON (t1.ID = t2.ID).

I'll take an example:

An ID can have multiple connections attached to it. Let Say:

Table1 ID : 0001

Number: 01

Table2 ID: 0001

Connection: J, K, S, O, P.

Now, when i do the above query, i would get a result of 3 rows new case types for ID 0001.

I would like to just get one, and the first priority will be put on the condition of (GE).

everytime I see a Number '01' and Connection 'J', I would ignore the other connection. If i do not see Number = '01' and Connection: 'J'. i would go for the rest of the conditions.

Hope you guys see what problem i am having.

Thanks,

Jul.

Try this:

SELECT CASE WHEN t1.Number = '01' THEN

CASE WHEN t2.Connection = 'J' THEN 'GE'

WHEN t2.Connection = 'K' THEN 'GPE'

WHEN t2.Connection = 'L' THEN 'GPA'

ELSE 'NOTHING' END

END AS NewType

FROM Table1 AS t1 LEFT JOIN Table2 AS t2

ON (t1.ID = t2.ID)

Since I do not like repeating the condition, I would do this:

SELECT CASE WHEN t1.Number = '01' THEN

CASE t2.Connection WHEN 'J' THEN 'GE'

WHEN 'K' THEN 'GPE'

WHEN 'L' THEN 'GPA'

ELSE 'NOTHING' END

END AS NewType

FROM Table1 AS t1 LEFT JOIN Table2 AS t2

ON (t1.ID = t2.ID)

|||Still, i get multiple results.....Thanks though.|||So you want only one row returned?

SELECT CASE WHEN t1.Number = '01' THEN

CASE t2.Connection WHEN 'J' THEN 'GE'

WHEN 'K' THEN 'GPE'

WHEN 'L' THEN 'GPA'

ELSE 'NOTHING' END

END AS NewType

FROM Table1 AS t1 LEFT JOIN (

select id, min(Connection) [Connection]

from Table2

group by id) AS t2

ON (t1.ID = t2.ID)

|||It works....Thanks sooo much.....